{"id":1107,"date":"2020-03-31T09:00:00","date_gmt":"2020-03-31T07:00:00","guid":{"rendered":"http:\/\/blogs.smbosque.es\/cienciasnaturales\/?p=1107"},"modified":"2020-03-30T20:21:55","modified_gmt":"2020-03-30T18:21:55","slug":"1o-pmar-ambito-cientifico-matematico-matematicas-sesion-12a-martes-31-marzo","status":"publish","type":"post","link":"https:\/\/blogs.smbosque.es\/cienciasnaturales\/2020\/03\/31\/1o-pmar-ambito-cientifico-matematico-matematicas-sesion-12a-martes-31-marzo\/","title":{"rendered":"1\u00ba PMAR. \u00c1MBITO CIENT\u00cdFICO MATEM\u00c1TICO. MATEM\u00c1TICAS. Sesi\u00f3n 12\u00aa. Martes 31. Marzo."},"content":{"rendered":"\n

Soluciones de los ejercicios de la\nsesi\u00f3n anterior P\u00e1gina 122:<\/strong><\/p>\n\n\n\n

Ejercicio 1:<\/strong><\/p>\n\n\n\n

a) x2\u20138x + 7= 0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) \u20132x \u20133= 0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) \u2013x \u20131= 0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 g) \u20137×2+ x +7 = 0<\/p>\n\n\n\n

Segundo grado\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Lineal\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Lineal\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Segundo grado<\/p>\n\n\n\n

b) x2\u20138x = 0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 d) x2+ 3= 0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 f) 5x + 3= 0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0 h) \u2013x2+ x \u20134 = 0<\/p>\n\n\n\n

Segundo grado\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Segundo grado\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Lineal\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Segundo grado<\/p>\n\n\n\n

Ejercicio 2:<\/strong><\/p>\n\n\n\n

a) x = \u20133,\n3                            f) x = \u20132\/3, 2\/3<\/p>\n\n\n\n

b) x = \u20131,\n1                            g) x = \u20133, 3\n<\/p>\n\n\n\n

c) x = \u20131,\n1                            h) x = \u20134\/5, 4\/5<\/p>\n\n\n\n

d) x = \u20135,\n5                            i) x = \u20133,\n3<\/p>\n\n\n\n

e) x = \u20133, 3                            j) x = \u20133, 3<\/p>\n\n\n\n

Para esta sesi\u00f3n vamos a aumentar un poquito la dificultad !!!!!!<\/p>\n\n\n\n

Os\ndejo dos v\u00eddeos para las ecuaciones de 2\u00ba grados incompletas:<\/p>\n\n\n\n

INCOMPLETAS<\/strong><\/p>\n\n\n\n

Video 1: <\/strong>https:\/\/www.youtube.com\/watch?v=UcUBxM-foys<\/a><\/p>\n\n\n\n

Video 2: <\/strong>https:\/\/www.youtube.com\/watch?v=huaOwD9_qcY<\/a><\/p>\n\n\n\n

– Realizamos los Ejercicios\nde la P\u00e1gina 122, lo intentamos solamente con\nel 3 y 4,<\/strong> y siguiendo los pasos del ejemplo de la p\u00e1gina 120.<\/p>\n","protected":false},"excerpt":{"rendered":"

Soluciones de los ejercicios de la sesi\u00f3n anterior P\u00e1gina 122: Ejercicio 1: a) x2\u20138x + 7= 0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 c) \u20132x \u20133= 0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 e) \u2013x \u20131= 0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 g) \u20137×2+ x +7 = 0 Segundo grado\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Lineal\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Lineal\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Segundo grado b) x2\u20138x = … Sigue leyendo →<\/span><\/a><\/p>\n","protected":false},"author":33,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[9],"tags":[],"class_list":["post-1107","post","type-post","status-publish","format-standard","hentry","category-1o-pmar"],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/blogs.smbosque.es\/cienciasnaturales\/wp-json\/wp\/v2\/posts\/1107","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/blogs.smbosque.es\/cienciasnaturales\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blogs.smbosque.es\/cienciasnaturales\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blogs.smbosque.es\/cienciasnaturales\/wp-json\/wp\/v2\/users\/33"}],"replies":[{"embeddable":true,"href":"https:\/\/blogs.smbosque.es\/cienciasnaturales\/wp-json\/wp\/v2\/comments?post=1107"}],"version-history":[{"count":2,"href":"https:\/\/blogs.smbosque.es\/cienciasnaturales\/wp-json\/wp\/v2\/posts\/1107\/revisions"}],"predecessor-version":[{"id":1109,"href":"https:\/\/blogs.smbosque.es\/cienciasnaturales\/wp-json\/wp\/v2\/posts\/1107\/revisions\/1109"}],"wp:attachment":[{"href":"https:\/\/blogs.smbosque.es\/cienciasnaturales\/wp-json\/wp\/v2\/media?parent=1107"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blogs.smbosque.es\/cienciasnaturales\/wp-json\/wp\/v2\/categories?post=1107"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blogs.smbosque.es\/cienciasnaturales\/wp-json\/wp\/v2\/tags?post=1107"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}